matlab - Get index of current element of a 2-D matrix within arrayfun -

let m matrix:

m = rand(1000, 2000);

consider following code example:

a = zeros(size(m)); row = 1:1000     col = 1:2000         a(row, col) = m(row,col)*(row + col);     end end

how compute matrix a without for loops?

there arrayfun function, don't know how index of current element:

a = arrayfun(@(x)(x*(index(1) + index(2))), m); %// how index???

perhaps there other solutions (and without loops)?

you can simple follows matrix represent row+col , multiply m

m = rand(1000, 2000); rowpluscol = bsxfun(@plus,(1:size(m,1)).',1:size(m,2)); = m.*rowpluscol;

from experience bsxfun extremely powerful function , can save run time, , perfect example of that.

Brazell