Exception Handling Java -

class chain_exceptions{    public static void main(string args[]){       try       {          f1();       }       catch(indexoutofboundsexception e)       {          system.out.println("a");          throw new nullpointerexception(); //line 0       }       catch(nullpointerexception e) //line 1       {          system.out.println("b");          return;       }       catch (exception e)       {          system.out.println("c");       }             {          system.out.println("d");       }       system.out.println("e");    }     static void f1(){       system.out.println("start...");       throw new indexoutofboundsexception( "parameter" );    } } 

i expected line 1 catch nullpointerexception thrown line 0 not happen.

but why ?.

when there catch block defined, why cant npe handler @ line1 catch ?

is because "throw" goes directly main() method ?

catch{ . . . } blocks associated try{ . . . } blocks. a catch block can catch exceptions thrown try block only. other catch blocks after first catch block not associated try block , hence when throw exception, not caught. or main() not catch exceptions.

a kind of each catch block trying do.

try{   try   {      f1();   }   catch(indexoutofboundsexception e)   {      system.out.println("a");      throw new nullpointerexception(); //line 0   } } catch(nullpointerexception e) //line 1 {      system.out.println("b");      return; }