c - Passing char arrays to a function -


the dreaded warning: passing argument 1 of ... makes integer pointer without cast

i don't understand this. trying pass simple string (yes, know character array) function. function parses string , returns first part. can please show me doing wrong? thank you!

char* get_request_type(char* buffer) {     char* p;     p = strtok(buffer, "|");     return p; }  int main() {     char buffer[30] = "test|something";     fprintf(stdout, "buffer: %s\n", buffer);  //<-- looks great needs parsing     char* request_type = get_request_type(buffer);  //<-- error here     fprintf(stdout, "%s\n", request_type); //<--expecting see 'test'  }

there may yet come day when comfortable working strings in c, day not day...

you didn't include string.h, compiler assume strtok defined as:

int strtok();

returns int , takes unknown number of arguments, it's call implicit function declaration. solution include string.h strtok declared.


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