XSLT : Copy whole xml document discarding specific parent nodes -


i have : 

<body>     foo bar foo bar foo bar...     <p>foo bar!</p>     <div class="iwantyourcontent">         <p>baz</p>     </div> </body>

i want output:

<body>     foo bar foo bar foo bar...     <p>foo bar!</p>     <p>baz</p> </body>

i have managed content of node using :

<xsl:template match="/">         <xsl:apply-templates select="//x:div[@class = 'iwantyourcontent']"/> </xsl:template>  <xsl:template match="//x:div[@class = 'iwantyourcontent']">     <body>         <xsl:copy-of select="node()"/>     </body> </xsl:template>

but i'm not able keep rest of document.

thanks helping.

the way sort of thing typically, identity template copies everything: 

<xsl:template match="node()|@*" >    <xsl:copy>       <xsl:apply-templates select="node()|@*" />    </xsl:copy> </xsl:template>

and make template match items want skip over:

<xsl:template match="div[@class='iwantyourcontent']" >    <xsl:apply-templates select="*" /> </xsl:template>

i.e. skip copy, because don't want div element copies, apply templates on further elements, because want copy descendants of div.

( if wanted skip contents entirely, leave template empty , have no content output @ all. )


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