mysqli - PHP: Trying to get property of non-object -


i working on function, returns whether table exists or not.

but notices:

notice: trying property of non-object [...] on line 10 

in

1  function table_exists($table) { 2       3      // database 4      global $mysqli; 5       6      // tables named $table 7      $result = $mysqli->query("show tables $table"); 8       9      // if result has more 0 rows 10     if($result->num_rows > 0) { 11         return true; 12     } else { 13         return false; 14     } 15 } 

the $mysqli var set this:

$mysqli = new mysqli(mysqli_host, mysqli_user, mysqli_password, mysqli_database); 

how solve that?

your sql syntax wrong. check value of variable $table. should have like

show tables "%" 

Comments

Popular posts from this blog

html - How to style widget with post count different than without post count -

How to remove text and logo OR add Overflow on Android ActionBar using AppCompat on API 8? -

javascript - storing input from prompt in array and displaying the array -