Optimize SQL Server Aggregation Query -


i'm looking ideas on how optimize query. i've evaluated execution plan not offer ideas missing index curious if writing query better (different tactics) result in faster/lighter query.

select [place], count([place])  (     select scoresid, replace(replace(eventplace1,'t', ''),'*','') [place]          [ms.prod]..mso_scores union     select scoresid, replace(replace(eventplace2,'t', ''),'*','')          [mso.prod]..mso_scores union     select scoresid, replace(replace(eventplace3,'t', ''),'*','')          [mso.prod]..mso_scores union     select scoresid, replace(replace(eventplace4,'t', ''),'*','')          [mso.prod]..mso_scores union     select scoresid, replace(replace(eventplace5,'t', ''),'*','')          [mso.prod]..mso_scores union     select scoresid, replace(replace(eventplace6,'t', ''),'*','')          [mso.prod]..mso_scores union     select scoresid, replace(replace(aaplace,'t', ''),'*','')          [mso.prod]..mso_scores ) data1  join [mso.prod]..mso_scores scores on scores.scoresid = data1.scoresid     , scores.usagnum = '274246'      , scores.teamresult='n' data1.place in ('1', '2', '3') group place

so quick explanation: there 6 event place fields. data in these fields looks "1", "2", "1t", "3", "5t"; "t" tie. care number, 1,2,3 parsing out "t" or "*" place , grouping query count.

how many 1st places have, how many 2nd places, , on..

try 1 (for 2008 , higher) -

select [place], count(1) (     select [place] = replace(replace(t.[place], 't', ''), '*', '')       dbo.mso_scores r     outer apply (         values              (eventplace1),             (eventplace2),             (eventplace3),             (eventplace4),             (eventplace5),             (eventplace6),             (aaplace)     ) t([place])     r.usagnum = '274246'          , r.teamresult = 'n' ) d d.place in ('1', '2', '3') group d.place

for additional information read topic: tips sql query optimization analyzing query plan


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