php - Count visitors of each day -


i've got array being generated mysql contains visitors of current week:

array     (         [0] => array             (                 [iid] => 2                 [mid] => 123456                 [name] => username                   [date] => 2013-09-03 18:19:23             )          [1] => array             (                 [iid] => 2                 [mid] => 123456                 [name] => username                  [date] => 2013-09-03 18:19:20             )          [2] => array             (                 [iid] => 2                 [mid] => 123456                 [name] => username                   [date] => 2013-09-03 18:10:42             )      ) 

each key visitor, need count each day how many visitors there in array.

this array should return:

mon: 0     tue: 3 wed: 0 etc 

as learned googling , finding count grouping multidimensional arrays in php have modified code , seems solve problem:

$inputarray  = array(     array('iid' => 5, 'mid' => '123456', 'name' => 'username', 'dd'  => '2013-09-03 18:19:23'),     array('iid' => 5, 'mid' => '123456', 'name' => 'username', 'dd'  => '2013-09-03 18:19:20'),     array('iid' => 5, 'mid' => '123456', 'name' => 'username', 'dd'  => '2013-09-03 18:10:42'),     array('iid' => 5, 'mid' => '123456', 'name' => 'username', 'dd'  => '2013-09-04 18:19:23'),     array('iid' => 5, 'mid' => '123456', 'name' => 'username', 'dd'  => '2013-09-04 18:19:23'));  $outputarray = array();  foreach ( $inputarray $record ) {      // first part of date string i.e. 2013-09-03     $day = explode(' ', $record['dd']);      // if date has not been added outputarray, add     if ( !key_exists($day[0], $outputarray) ) {         $outputarray[$day[0]] = 0;     }     $outputarray[$day[0]] += 1; }  echo '<pre>'; print_r($outputarray); 

output:

array (     [2013-09-03] => 3     [2013-09-04] => 2 ) 

you can test copying , pasting here http://writecodeonline.com/php/


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