Wireshark filter per ip address "different from" something -


i'd captured packets in origin or destination ip address different from, say, 192.168.0.1. purpose tried ip.addr != 192.168.0.1, filter turns yellow, instead of green, must wrong.

how can (correctly) done?

6.4.4. common mistake

[warning] warning! using != operator on combined expressions like: eth.addr, ip.addr, tcp.port, udp.port , alike not work expected!

often people use filter string display ip.addr == 1.2.3.4 display packets containing ip address 1.2.3.4.

then use ip.addr != 1.2.3.4 see packets not containing ip address 1.2.3.4 in it. unfortunately, not expected.

instead, expression true packets either source or destination ip address equals 1.2.3.4. reason this, expression ip.addr != 1.2.3.4 must read "the packet contains field named ip.addr value different 1.2.3.4". ip datagram contains both source , destination address, expression evaluate true whenever @ least 1 of 2 addresses differs 1.2.3.4.

if want filter out packets containing ip datagrams or ip address 1.2.3.4, correct filter !(ip.addr == 1.2.3.4) reads "show me packets not true field named ip.addr exists value of 1.2.3.4", or in other words, "filter out packets there no occurrences of field named ip.addr value 1.2.3.4".

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