c++ - "print 1 to n" function prints 1 twice - 


 void printint(int n){    if(n==1)      cout<<1<<" ";    else      printint(n-1);      cout<<n<<" ";   }

the output is

 1 1 2 3....n

i'm writing out actual steps of function on piece of paper don't how printing 1 in console (visual studio 2010). past hw solutions strictly understanding how works.

you need braces:

   if(n==1)    {      cout<<1<<" ";    }    else    {      printint(n-1);      cout<<n<<" ";    }

or else second cout gets run when n==1. strictly speaking braces around first cout aren't required, style in case.

editorial note: problem solved stepping through function in debugger.


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