java - Matcher don't find on 2nd loop -

1st step everyth ok, on 2nd step goes someth wrong: slow (20+ sec) on find(). besides matches() returs false, , don't know why. separately every regex works fine. using emulator. thax guys.

    string[] regexcontent = {"node[\\s\\s]*?(<p>[\\s\\s]+</p>)",  "([\\s\\s]*?)</div>"};      pattern p;     matcher m;           (string regex : regexcontent){               p = pattern.compile(regex);             m = p.matcher(result);              //if (m.matches()) // false             result = "";             if (m.find()) // on 2nd step waits long time & don't find                 result = m.group(m.groupcount());             m.reset();          } 

if need reuse string derived matcher.group, better create new string since matcher.group still substring reference pointing original one. when second time read reference , pass pattern.matcher(), not pass exact string first step. maybe it's bug or it's designed work way. situation, create new string each time matcher.group() makes life easier. hope explained correctly , completely.

string[] regexcontent = {"node[\\s\\s]*?(<p>[\\s\\s]+</p>)",  "([\\s\\s]*?)</div>"};  pattern p; matcher m;       (string regex : regexcontent){           p = pattern.compile(regex);         m = p.matcher(result);          //if (m.matches()) // false         result = "";         if (m.find()) // on 2nd step waits long time & don't find             result = new string(m.group(m.groupcount()));         m.reset();      }