java - Can changes in the order of the method parameters be called method overloading? -


please note order of parameters changed in below example. question - can call below example of method overloading? 

public void show(string s, int a){     system.out.println("test.show(string, int)"); } public void show(int s, string a){     system.out.println("test.show(int, string)"); }

yes, that's absolutely method overloading.

from section 8.4.9 of jls:

if 2 methods of class (whether both declared in same class, or both inherited class, or 1 declared , 1 inherited) have same name signatures not override-equivalent, method name said overloaded.

"override-equivalent" described in section 8.4.2:

two methods have same signature if have same name , argument types.

[ ... details on "same argument types ... ]

the signature of method m1 subsignature of signature of method m2 if either:

  • m2 has same signature m1, or

  • the signature of m1 same erasure (§4.6) of signature of m2.

two method signatures m1 , m2 override-equivalent iff either m1 subsignature of m2 or m2 subsignature of m1.


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