Regular Language to DFA conversion -


i ran problem in textbook can't decipher , hoping help. i'm not asking solution, translation, or push in right direction. in jflap textbook.

the alphabet consists of "a".

{a^l |l = 0 (mod 6), l /= 0 (mod 4) }

construct dfa recognizes language.

i assume if string of a's multiple of 6 string accepted, don't understand l/= 0 mean. there multiple questions this.

again, don't need, or want, answer problem, maybe translation english sentence me understand asking for.

l /= 0 (mod 4) means l not congruent 0 mod 4 (the opposite of l = 0 (mod 4))

when write hand, put slash through symbol (like ≠)


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