java - unicode regex pattern not working -

i trying match unicode charaters sequence:

pattern pattern = pattern.compile("\\u05[ddee][0-9a-fa-f]{2,}");     string text = "\\n     \\u05db\\u05d3\\u05d5\\u05e8\\u05d2\\u05dc\\n    <\\/span>\\n<br style=\\";     matcher match = pattern.matcher(text); 

but doing gives exception:

exception in thread "main" java.util.regex.patternsyntaxexception: illegal unicode escape sequence near index 4   \u05[ddee][0-9a-fa-f]+       ^ 

how can use still use regex regex chars (like "[") match unicode?

edit: i'm trying parse text. text somewhere has sequence of unicode characters, know code range.

edit2: using ranges instead : [\\u05d0-\\u05ea]{2,} still can't match text above

edit3: ok, it's working, problem used two backslashes instead of one, both in regex , text. solution is, assuming know there 2 chars or more:

[\u05d0-\u05ea]{2,} 

here causing exception:

\\u05[ddee][0-9a-fa-f]}{2,}   ^^^^ 

the java regular expression parser thinks trying match unicode code point using escape sequence \unnnn giving exception, because \u requires 4 hexadecimal digits after , there 2 of them, namely 05 need change \\u0005 if want.

on other hand, if want match \\u in target string, need quad escape each backslash \ \\\\ match \\u need \\\\\\\\u.

\\\\\\\\u05[ddee][0-9a-fa-f]}{2,} 

finally, if want match unicode code points literally in target string need modify our last expression bit this:

(?:\\\\\\\\u05[ddee][0-9a-fa-f]){2,} 

edit: since there 1 backslash in target string regular expression should be:

(?:\\\\u05[ddee][0-9a-fa-f]){2,} 

this match \u05db\u05d3\u05d5\u05e8\u05d2\u05dc in string

<\/span><\/span><span dir=\"rtl\">\n \u05db\u05d3\u05d5\u05e8\u05d2\u05dc\n <\/span>\n<br style=\"clear : both; font-size : 1px;\">\n<\/div>"}, 200, null, null); 

edit 2: if want match literal \u05db\u05d3\u05d5\u05e8\u05d2\u05dc can't use range.

on other hand, if want match unicode code points between 05d0 , 05df can use:

(?:[\\u05d0\\u05df]){2,}