python - Strip off characters from output -


i have following structure generated bs4, python.

['y10765227', '9884877926, 9283183326', '', 'dealer', 'rgmuthu'] ['l10038779', '9551154555', ',', ','] ['r10831945', '9150000747, 9282109134, 9043728565', ',', ','] ['b10750123', '9952946340', '', 'dealer', 'bala'] ['r10763559', '9841280752, 9884797013', '', 'dealer', 'senthil']

i wanna rip characters off , should following

9884877926, 9283183326, dealer, rgmuthu 9551154555 9150000747, 9282109134, 9043728565 9952946340 , dealer, bala 9841280752, 9884797013, dealer, senthil

i using print re.findall("'([a-za-z0-9,\s]*)'", eachproperty['onclick'])

so wanna remove "[]" , "''" , "," , random id in start.

update

onclick="try{appendpropertyposition(this,'y10765227','9884877926, 9283183326','','dealer','rgmuthu');jsb9onunloadtracking();jsevt.stopbubble(event);}catch(e){};"

so scraping onclick attribute above mentioned data.

you can use combination of str.join , str.translate here:

>>> string import punctuation, whitespace >>> lis = [['y10765227', '9884877926, 9283183326', '', 'dealer', 'rgmuthu'], ['l10038779', '9551154555', ',', ','],['r10831945', '9150000747, 9282109134, 9043728565', ',', ','], ['b10750123', '9952946340', '', 'dealer', 'bala'], ['r10763559', '9841280752, 9884797013', '', 'dealer', 'senthil']] item in lis:     print ", ".join(x x in item[1:]                                   if x.translate(none, punctuation + whitespace)) ...      9884877926, 9283183326, dealer, rgmuthu 9551154555 9150000747, 9282109134, 9043728565 9952946340, dealer, bala 9841280752, 9884797013, dealer, senthil

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